Upcoming-ExamsFinance-Account-AssistantFAA-MATHSFAA Mathematics — Detailed Study Plan

🔢 FAA MATHEMATICS — The 10-Mark Plan

Section: Mathematics · 10 of 120 marks · 10 syllabus topics · 1 question each Companions: Maths-Analysis-and-Mapping (the evidence) · Maths-Tagged-Answers (all 12 PYQs solved)

⭐ Read this before you open a single book

1. The 2024 paper asked exactly ONE question from EACH of the 10 topics, in syllabus order. Same design as Statistics. You know precisely where every mark comes from. 2. ⚠️ This is NCERT Class 11–12 mathematics — NOT SSC-style quantitative aptitude. Limits, derivatives, matrices, determinants, 3-D geometry, vectors. There is ZERO percentage, profit-loss, time-and-work, ratio, average, or speed-distance content. If you were about to buy a quant aptitude book, don't — it will not help you here. 3. ⭐ Probability is worth TWO marks, because it is also Statistics topic (vi). Study it once, get paid twice.

Total time needed: ~20–24 hours.Realistic target: 7–8 / 10.


PART 1 — The strategy in one box

Four rules for this section

  1. Never skip a topic. One skipped topic = exactly one lost mark, guaranteed.
  2. Never go deeper than one question's worth. Depth beyond that is wasted time — see the depth ladder below.
  3. Learn to judge STATEMENTS, not just to calculate. 6 of the 10 questions in 2024 were multi-statement or matching. That is the real difficulty.
  4. Skip every proof and every derivation. Not one has ever been asked.

PART 2 — ⭐ HOW DEEP? The depth ladder

This is the single most important table in this plan. For each topic, only one question is coming, so the scope boundary matters more than the content.

LevelWhat it meansWhich topics
L1 — Recall onlyMemorise the rule. No practice sums needed.(vii) Determinants properties · half of (iv) Limits
L2 — One-step formulaKnow the formula and plug numbers in. 5–10 practice sums.(i) Interest · (x) Vectors · (ix) Distance / area
L3 — Two-step / methodA short method with 2–3 steps. 10–15 practice sums.(ii) Linear equations · (iii) P&C · (v) Sets · (viii) Probability
L4 — Concept judgementYou must decide whether a statement is true. Needs understanding, not speed.(vi) Relations & Functions · statement parts of (iii), (iv), (vii)
DO NOT STUDY THESE — they have never been asked and are not worth the hours

  • Proofs of anything (no proof has ever appeared)
  • Continuity & differentiability theory, Rolle's / Lagrange's mean value theorems
  • Applications of derivatives — maxima/minima, tangents & normals, rate of change
  • Integration in any form — it is not on the syllabus at all
  • Inverse trigonometric functions, differential equations, linear programming
  • Adjoint / inverse of a matrix, solving systems by matrix method, Cramer's rule (only determinant properties were asked)
  • Conic sections — parabola, ellipse, hyperbola
  • Vector / scalar triple product beyond the area formula
  • Bayes' theorem and conditional-probability trees (borderline — 15 minutes of reading, no more)
  • Binomial theorem general term / middle term — only a plain expansion was asked

PART 3 — Topic-by-topic: scope, formulas, and time

🟢 EASY TIER — one-step formulas (4.5 hrs → ~3 marks)

(i) Simple / Compound Interest · L2 · 1.5 hrs

Source: any Class 8 arithmetic chapter. Not in NCERT 11–12.

SI=P×R×T100A=P(1+R100)nCI=APSI = \frac{P \times R \times T}{100} \qquad A = P\left(1 + \frac{R}{100}\right)^{n} \qquad CI = A - P

Also know:

  • Half-yearly: rate ÷ 2, time × 2 · Quarterly: rate ÷ 4, time × 4
  • Difference between CI and SI for 2 years =P(R100)2= P\left(\frac{R}{100}\right)^2
🎯 2024 · Q81 — ₹54,000 for 9 months at 8% → 3240

⚠️ The whole trap was the 9 months. T must be in years → 9/12 = 0.75. Always convert months to years first.

Depth stop: ✋ no instalments, no compound-interest-with-changing-rates, no depreciation.

(x) Vectors · L2 · 1.5 hrs

Source: NCERT Class 12, Chapter 10.

a=a12+a22+a32a^=aaopposite unit vector=a^|\vec{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2} \qquad \hat{a} = \frac{\vec{a}}{|\vec{a}|} \qquad \text{opposite unit vector} = -\hat{a}

ab=a1b1+a2b2+a3b3=abcosθ\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3 = |\vec a||\vec b|\cos\theta

Also know: perpendicular ⇒ dot product = 0 · parallel ⇒ cross product = 0 · i^,j^,k^\hat{i}, \hat{j}, \hat{k} are unit vectors along the axes.

🎯 2024 · Q90 — unit vector opposite to (1, −1) → −(1/√2)(1, −1)

⚠️ The trap: (−1, 1) points the right way but has magnitude √2 — it is not a unit vector. Divide by the magnitude.

Depth stop: ✋ no triple products, no vector equations of lines/planes, no projection formulae.

(ii) Linear Equations in Two Variables · L3 · 1.5 hrs

Source: NCERT Class 10, Chapter 3.

For a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0:

ConditionMeaning
a1a2b1b2\dfrac{a_1}{a_2} \ne \dfrac{b_1}{b_2}Unique solution (lines intersect)
a1a2=b1b2c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \ne \dfrac{c_1}{c_2}No solution (parallel)
a1a2=b1b2=c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2}Infinite solutions (coincident)
🎯 2024 · Q82 — 2 burgers + 1 drink = ₹70, 1 burger + 2 drinks = ₹50 → ₹30 / ₹10

Exam shortcut: with four options given, substitute the options — far faster than elimination.

Depth stop: ✋ no three-variable systems, no graphical solution plotting.


🟡 MODERATE TIER — a real method (8 hrs → ~4 marks)

(v) Set Theory · L3 · 2 hrsasked in BOTH papers

Source: NCERT Class 11, Chapter 1.

ABABABA=UAA \cup B \qquad A \cap B \qquad A - B \qquad A' = U - A Symmetric difference: AB=(AB)(AB)=(AB)(BA)\textbf{Symmetric difference: } A \triangle B = (A \cup B) - (A \cap B) = (A-B) \cup (B-A) n(AB)=n(A)+n(B)n(AB)n(A \cup B) = n(A) + n(B) - n(A \cap B) De Morgan: (AB)=AB(AB)=AB\textbf{De Morgan: } (A \cup B)' = A' \cap B' \qquad (A \cap B)' = A' \cup B'

Modulus → interval conversion — this decided 2024·Q85:

  • |x| < a \Rightarrow -a < x < a
  • |x| > a \Rightarrow x < -a \text{ or } x > a
  • xkaxk+a or xka|x - k| \ge a \Rightarrow x \ge k+a \text{ or } x \le k-a

Also: number of subsets of a set with n elements = 2n2^n · power set.

🎯 BOTH papers. 2022·Q32 symmetric difference → {1,2,5,6,7} · 2024·Q85 interval sets → [1, 2)

⚠️ 2024·Q85 turned entirely on bracket types — whether 1 and 2 were included. Two options differed only there. Draw the number line.

Depth stop: ✋ no cardinality theory, no infinite sets, no relations-on-sets proofs.

(ix) Coordinate & 3-D Geometry · L2/L3 · 2 hrsasked in BOTH papers

Source: NCERT Class 11 Ch 10 (straight lines) + Ch 12 (3-D basics) · Class 12 Ch 11.

Distance: d=(x2x1)2+(y2y1)2+(z2z1)2\textbf{Distance: } d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2} Midpoint: (x1+x22,y1+y22)Section (m:n): (mx2+nx1m+n,my2+ny1m+n)\textbf{Midpoint: } \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right) \qquad \textbf{Section (m:n): } \left(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n}\right) Area of triangle (2-D): 12x1(y2y3)+x2(y3y1)+x3(y1y2)\textbf{Area of triangle (2-D): } \tfrac{1}{2}\left|x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)\right| ⭐ Area of triangle (3-D): 12AB×AC⭐\ \textbf{Area of triangle (3-D): } \tfrac{1}{2}\left|\vec{AB} \times \vec{AC}\right| Slope: m=y2y1x2x1Line: yy1=m(xx1)\textbf{Slope: } m = \frac{y_2-y_1}{x_2-x_1} \qquad \textbf{Line: } y - y_1 = m(x-x_1)

Collinearity: three points are collinear if the area of the triangle = 0.

🎯 BOTH papers. 2022·Q37 distance → 11.4 · 2024·Q89 area in 3-D

⚠️ 2024·Q89 has NO correct option — the true area is √17 ≈ 4.123 and the options were √20, √23, √26, √29. See Maths-Tagged-Answers. Learn the method, ignore that answer key.2022·Q37 shortcut: √130 sits between √121 = 11 and √144 = 12 — estimate, don't compute.

Depth stop: ✋ no conic sections, no direction cosines/ratios beyond the basics, no plane equations.

(viii) Probability · L3 · 2 hrs ⭐⭐ WORTH TWO MARKS

Source: NCERT Class 11, Chapter 16. You have already written this up — see ST-6-Theory-of-Probability.

0P(A)1P(A)=favourabletotalP(A)+P(Aˉ)=10 \le P(A) \le 1 \qquad P(A) = \frac{\text{favourable}}{\text{total}} \qquad P(A) + P(\bar A) = 1 P(AB)=P(A)+P(B)P(AB)independent: P(AB)=P(A)P(B)P(A \cup B) = P(A) + P(B) - P(A \cap B) \qquad \text{independent: } P(A \cap B) = P(A)\cdot P(B)

Standard values worth knowing cold: a card is a King = 4/52 = 1/13 · a diamond = 13/52 = 1/4 · a face card = 12/52 · heads = 1/2 · a six = 1/6.

🎯 THREE questions across the two papers — 2024·Q88 (maths), 2024·Q76 (statistics), 2022·Q34 (statistics)

In 2022·Q34, options b, c, d were 1½, 2½ and 3½ — all greater than 1, so none can be a probability. The range rule alone killed three of four options. ⭐ In 2024·Q88, "a number between 1 and 6 on a die" is a CERTAIN event (P = 1) — so it must come last. That alone eliminated three options.

Depth stop: ✋ Bayes' theorem — read once, don't drill. No random variables, no distributions.

(iii) Permutations, Combinations & Binomial Theorem · L3/L4 · 2 hrs

Source: NCERT Class 11, Ch 7 (P&C) + Ch 8 (Binomial).

nPr=n!(nr)!nCr=n!r!(nr)!nCr=nCnr^nP_r = \frac{n!}{(n-r)!} \qquad ^nC_r = \frac{n!}{r!\,(n-r)!} \qquad ^nC_r = {}^nC_{n-r} ⭐ Word with repeated letters: n!p!q!r!⭐\ \textbf{Word with repeated letters: } \frac{n!}{p!\,q!\,r!} (a+b)n=k=0nnCkankbk(a+b)3=a3+3a2b+3ab2+b3(a+b)^n = \sum_{k=0}^{n} {}^nC_k\, a^{n-k} b^k \qquad (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

The distinction that gets tested: order matters → permutation · order does not matter (a committee, a selection) → combination. n people in a row = n!n! · n people in a circle = (n1)!(n-1)!

🎯 2024 · Q83 — PEPPER = 6!3!2!=60\frac{6!}{3!2!} = 60 ✓ · committee =(203)= \binom{20}{3} ✓ · (2+x)3(2+x)^3 coefficients 12 then 6, not 6 then 12 ✗ · 6 people in a row = 720, not 360 ✗

⚠️ Learn (a+b)3(a+b)^3 cold. The paper simply swapped two coefficients and expected you not to notice.

Depth stop: ✋ no general/middle-term formulas, no circular permutations with restrictions, no derangements.


🔴 HARD TIER — needs precision (7.5 hrs → ~3 marks)

(vii) Matrices & Determinants · L1 · 2 hrshighest recall-per-mark in the section

Source: NCERT Class 12, Ch 3 + Ch 4properties only.

RuleResult
Identity matrixdet(I)=1\det(I) = 1
Two identical rows (or columns)det=0\det = 0
A whole row or column of zerosdet=0\det = 0
Diagonal / triangular matrix$\det = $ product of the diagonal entries
Transposedet(AT)=det(A)\det(A^T) = \det(A)
Productdet(AB)=det(A)det(B)\det(AB) = \det(A)\cdot\det(B)
Scalar multiple (n×n)det(kA)=kndet(A)\det(kA) = k^n \det(A)
Swap two rowsdeterminant changes sign
Inversedet(A1)=1/det(A)\det(A^{-1}) = 1/\det(A)
Singular matrixdet=0\det = 0 ⇒ no inverse

2×2 determinant: abcd=adbc\begin{vmatrix} a & b \\ c & d \end{vmatrix} = ad - bc

🎯 2024 · Q87 tested FIVE of these rules in ONE question — identical rows → 0 · det(I)=1\det(I) = 1 · diag(1,2,3) → 6 · det(PQT)=2×4=8\det(PQ^T) = 2 \times 4 = 8

This is the best two hours in the whole plan. Pure recall, no practice sums, and it has already produced a full mark.

Depth stop:no adjoint, no inverse computation, no Cramer's rule, no solving equations by matrices. Only properties.

(iv) Limits & Derivatives · L1/L4 · 2.5 hrs

Source: NCERT Class 11, Chapter 13.

⭐ First principles: f(x)=limh0f(x+h)f(x)h⭐\ \textbf{First principles: } f'(x) = \lim_{h \to 0}\frac{f(x+h) - f(x)}{h}

Standard limits — memorise these five: limxaxnanxa=nan1limx0sinxx=1⭐ limx0ex1x=1\lim_{x\to a}\frac{x^n - a^n}{x-a} = n a^{n-1} \qquad \lim_{x\to 0}\frac{\sin x}{x} = 1 \qquad ⭐\ \lim_{x\to 0}\frac{e^x - 1}{x} = 1 limx0log(1+x)x=1limx0ax1x=logea\lim_{x\to 0}\frac{\log(1+x)}{x} = 1 \qquad \lim_{x\to 0}\frac{a^x - 1}{x} = \log_e a

Derivatives — memorise these: ddx(xn)=nxn1⭐ ddx(1x)=1x2ddx(ex)=exddx(logx)=1x\frac{d}{dx}(x^n) = nx^{n-1} \qquad ⭐\ \frac{d}{dx}\left(\frac{1}{x}\right) = -\frac{1}{x^2} \qquad \frac{d}{dx}(e^x) = e^x \qquad \frac{d}{dx}(\log x) = \frac{1}{x} ddx(sinx)=cosxddx(cosx)=sinxddx(c)=0\frac{d}{dx}(\sin x) = \cos x \qquad \frac{d}{dx}(\cos x) = -\sin x \qquad \frac{d}{dx}(c) = 0

Product rule (uv)=uv+uv(uv)' = u'v + uv' · Quotient rule (uv)=uvuvv2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}

The 0/0 trick: if substitution gives 0/0, factorise and cancel. x21x1=x+12\frac{x^2-1}{x-1} = x+1 \to 2 at x=1x=1.

🎯 2024 · Q84 — the two FALSE statements were: limx21x1=0\lim\frac{x^2-1}{x-1} = 0 (it is 2) and ddx(1/x)=+1/x2\frac{d}{dx}(1/x) = +1/x^2 (it is negative)

⚠️ Both traps were sign / arithmetic slips, not hard theory. The paper rewards precision, not cleverness.

Depth stop: ✋ no continuity/differentiability theory, no L'Hôpital, no second derivatives, no applications of derivatives at all.

(vi) Relations and Functions · L4 · 3 hrsthe hardest to judge

Source: NCERT Class 11 Ch 2 + Class 12 Ch 1.

TermMeaningQuick test
FunctionEach x gives exactly one yVertical line test — a circle fails
One-one (injective)Different x → different yHorizontal line test; y=x2y = x^2 fails
Onto (surjective)Range = codomainEvery y is hit
BijectiveBoth one-one and onto
DomainAllowed x values
RangeResulting y values

Composition: (ff)(x)=f(f(x))(f \circ f)(x) = f(f(x)) — substitute the function into itself.

Ranges worth knowing: y=x2[0,)y = x^2 \Rightarrow [0,\infty) · y=x2k[k,)y = x^2 - k \Rightarrow [-k,\infty) · y=kx2(,k]y = k - x^2 \Rightarrow (-\infty, k] Monotonicity: y=x2y = x^2 is increasing on (0, ∞) but not on ℝ.

🎯 2024 · Q86x2+y2=25x^2 + y^2 = 25 is a circle ⇒ not a function · y=2x+1ff=4x+3y = 2x+1 \Rightarrow f\circ f = 4x+3 · y=x2y = x^2 increasing on (0,∞) only

⚠️ One pair in that question was mis-stated by the paper — see Maths-Tagged-Answers. The answer still followed by elimination. When a matching question has one bad pair, anchor on the pairs you are certain of and eliminate.

Depth stop: ✋ no equivalence relations, no binary operations, no inverse functions.


PART 4 — ⭐ THE COMPLETE FORMULA SHEET (one page)

INTERESTSI=PRT100SI = \frac{PRT}{100} · A=P(1+R100)nA = P(1+\frac{R}{100})^n · CI = A − P · months → years!

LINEAR EQ — unique a1a2b1b2\frac{a_1}{a_2} \ne \frac{b_1}{b_2} · none a1a2=b1b2c1c2\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2} · infinite all three equal

P & CnPr=n!(nr)!^nP_r = \frac{n!}{(n-r)!} · nCr=n!r!(nr)!^nC_r = \frac{n!}{r!(n-r)!} · repeated letters n!p!q!\frac{n!}{p!q!} · row n!n! · circle (n1)!(n-1)! (a+b)3=a3+3a2b+3ab2+b3(a+b)^3 = a^3+3a^2b+3ab^2+b^3

LIMITSxnanxanan1\frac{x^n-a^n}{x-a}\to na^{n-1} · sinxx1\frac{\sin x}{x}\to1 · ex1x1\frac{e^x-1}{x}\to1 · log(1+x)x1\frac{\log(1+x)}{x}\to1 DERIVATIVES(xn)=nxn1(x^n)'=nx^{n-1} · (1/x)=1/x2(1/x)' = -1/x^2 · (ex)=ex(e^x)'=e^x · (logx)=1/x(\log x)'=1/x · first principles limh0f(x+h)f(x)h\lim_{h\to0}\frac{f(x+h)-f(x)}{h}

SETSAB=(AB)(AB)A\triangle B=(A\cup B)-(A\cap B) · n(AB)=n(A)+n(B)n(AB)n(A\cup B)=n(A)+n(B)-n(A\cap B) · De Morgan · subsets =2n=2^n x<aa<x<a|x|<a \Rightarrow -a<x<a · xkaxk+a|x-k|\ge a \Rightarrow x\ge k+a or xkax\le k-a

FUNCTIONS — vertical line test = is it a function · horizontal line test = one-one · ff(x)=f(f(x))f\circ f(x)=f(f(x))

DETERMINANTSdet(I)=1\det(I)=1 · identical rows =0=0 · diagonal == product · det(AT)=det(A)\det(A^T)=\det(A) · det(AB)=detAdetB\det(AB)=\det A \det B · 2×2 =adbc= ad-bc

PROBABILITY0P10\le P\le1 · P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B) · independent P(A)P(B)\Rightarrow P(A)P(B) · King 1/13 · diamond 1/4

COORDINATEd=(Δ)2d=\sqrt{\sum(\Delta)^2} · midpoint · section formula · 3-D area =12AB×AC=\frac12|\vec{AB}\times\vec{AC}| · collinear ⇒ area 0

VECTORSa=a12+a22+a32|\vec a|=\sqrt{a_1^2+a_2^2+a_3^2} · a^=a/a\hat a = \vec a/|\vec a| · opposite =a^=-\hat a · \perp \Rightarrow dot =0=0


PART 5 — The 8-week schedule

~3 hours a week, alongside your main sections. Maths sits in Week 9 of FAA-MASTER-PLAN but is far better spread thin.

WeekTopicsHrsCheckpoint
1(i) Interest · (x) Vectors3SI/CI in under 30 s; unit vector by heart
2(ii) Linear equations · (v) Sets start3The three solution conditions; symmetric difference
3⭐ (v) Sets finish — modulus to intervals2Convert x11\|x-1\|\ge1 to intervals on a number line
4⭐ (ix) Coordinate & 3-D3Distance formula; ½|AB × AC|
5⭐⭐ (viii) Probability2.5Also covers Statistics (vi) — two marks
6(iii) P & C + Binomial3PEPPER-type; (a+b)3(a+b)^3 cold
7⭐ (vii) Determinants (pure recall — easiest hours here) · (iv) Limits start3Recite all 9 determinant rules
8(iv) Limits finish · (vi) Relations & Functions3.55 standard limits; vertical/horizontal line tests
FinalRe-solve all 12 PYQs from Maths-Tagged-Answers1.59+/11 valid

PART 6 — Exam-day approach

10 questions. Give them ~10 minutes, in your second pass — after GK and theory, before the long Accountancy sums.

OrderDoWhy
1stQ on interest, vectors, distanceOne formula, 30 seconds each
2ndDeterminants matchingPure recall — no calculation at all
3rdSets, probability, linear equationsShort method, 1 minute each
4thMulti-statement questions (P&C, limits)Judge each claim separately
LastRelations & Functions matching, and any 3-D areaSlowest; anchor on the pairs you are sure of
⭐ Three eliminations that cost zero time

  1. Any probability option greater than 1 is impossible. (Killed 3 of 4 options in 2022·Q34.)
  2. In matching questions, anchor on the ONE pair you are certain of and delete every option that contradicts it. (This solved 2024·Q86 and Q87 without checking all four pairs.)
  3. In "which statements are correct", find the single clearly-FALSE claim first — it usually removes two options at once.

Negative marking is −0.25. Break-even is 25%, so attempt anything where you can eliminate even one option. With this section, you should be attempting all 10.


PART 7 — Traps seen in the two papers

TrapGuard
Time given in monthsConvert to years — 9 months = 9/12
(2+x)3(2+x)^3 coefficients12 then 6 — the paper swaps them
"3 boys and 3 girls in a row"6!=7206! = 720; 360 is the alternating arrangement
ddx(1/x)\frac{d}{dx}(1/x)NEGATIVE1/x2-1/x^2
limx21x1\lim\frac{x^2-1}{x-1} at x=1x=1Factorise → 2, not 0
Bracket types in interval answers[1,2)[1,2) vs [1,2][1,2]draw the number line
det(QT)\det(Q^T)Equals det(Q)\det(Q) — the transpose changes nothing
"A number between 1 and 6" on a dieCertain event, P = 1
Unit vector questionsMust divide by the magnitude — (−1,1) is not a unit vector
Symmetric differenceRemoves the intersection
A matching question with one odd pairAnchor on the certain pairs and eliminate
⚠️ Expect one broken question

2024·Q89 had no correct option (true area √17; options √20/√23/√26/√29). If you meet a question where your correct working matches nothing, do not burn three minutes re-checking. Mark the nearest option, move on, and come back only if time allows.


PART 8 — What to study from

TopicSource
(i) InterestAny Class 8 arithmetic chapter
(ii) Linear equationsNCERT Class 10, Ch 3
(iii) P & C · BinomialNCERT Class 11, Ch 7 and Ch 8
(iv) Limits & DerivativesNCERT Class 11, Ch 13
(v) SetsNCERT Class 11, Ch 1
(vi) Relations & FunctionsNCERT Class 11 Ch 2 + Class 12 Ch 1
(vii) Matrices & DeterminantsNCERT Class 12, Ch 3 and Ch 4properties only
(viii) ProbabilityNCERT Class 11, Ch 16 — or just use ST-6-Theory-of-Probability
(ix) Coordinate & 3-DNCERT Class 11 Ch 10 and Ch 12
(x) VectorsNCERT Class 12, Ch 10
Read only the solved examples and the summary box at the end of each NCERT chapter.

Skip the exercises except for the topics marked L2/L3 above. NCERT exercises go far deeper than one MCQ ever will.


🎯 IF YOU REMEMBER NOTHING ELSE

This is NCERT 11–12, not aptitude. Do not buy a quant book.

Probability is two marks — one here, one in Statistics. Do it once, properly.

Determinant properties are the cheapest mark on the paper — nine rules, pure recall, two hours, and 2024 tested five of them in a single question.

Set Theory and Coordinate Geometry appeared in BOTH papers. If you are short on time, these two go first.

The difficulty is the format, not the maths. Six of ten questions make you judge four separate claims. Practise reading statements, not just solving sums.

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